[ANSWER] MAT350 8.5 MATLAB: Least Squares Approximation

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MAT350 8.5 MATLAB: Least Squares Approximation

In this activity you will use a least squares approximation to find a curve of best fit for a data set.

Consider the four points in the plane:  (-2, 3), (-1, 1), (1, 0), and (2, 1).  Use the least squares approximation to find the best-fit line for this data.

Enter the data as two column vectors.  Note Y is the vector b in the inconsistent system Ax=b.

X = [-2 -1 1 2].’

Y = [3 1 0 1].’

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MAT350 8.5 MATLAB: Least Squares Approximation

In this activity you will use a least squares approximation to find a curve of best fit for a data set.

Consider the four points in the plane:  (-2, 3), (-1, 1), (1, 0), and (2, 1).  Use the least squares approximation to find the best-fit line for this data.

Enter the data as two column vectors.  Note Y is the vector b in the inconsistent system Ax=b.

X = [-2 -1 1 2].’

Y = [3 1 0 1].’

 

Use the length() command to determine the size of the column vector.

m = length(X)

Set up the appropriate matrix A to find the best-fit line of the form y=C+Dx.  The first column of A will contain all 1’s.  This is achieved here using the ones() command to create a column vector of length m of all 1’s.  The second column of A contains X.

A = [ones(m,1) X]

Calculate the matrix products.

A_transposeA = A.’ * A

A_transposeY = A.’ * Y

Use the backslash operation to solve the overdetermined system.

Soln1 = A_transposeA\A_transposeY

 

Generate points to plot the best-fit line.  The points will range from -4 to 4 in increments of 0.1.

x=-4: 0.1 :4

ylinear = Soln1(1) + Soln1(2)*x

 

The following sequence of commands plots the data and the line of best fit.

plot(x, ylinear, X, Y, ‘k*’);grid;shg

 

The same data is used for the activity.  These are provided

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for you.

X = [-2 -1 1 2].’

Y = [3 1 0 1].’

 

Use the length() command to determine the size of the column vector X.  Store this value in m.

m = length(X);

Set up the appropriate matrix A to find the best-fit parabola of the form y=C+Dx+Ex^2.  The first column of A will contain all 1’s, using the ones() command.  The second column of A contains x values that are stored in X.  The third column of A contains the squared x values that are stored in X.  Elementwise multiplication of X by itself, using .* operator, will produce the desired values for the third column.

A = [ones(m,1) X X.*X];

Calculate the matrix products.  These are provided for you.

A_transposeA = A.’ * A

A_transposeY = A.’ * Y

 

Use the backslash operation to solve the overdetermined system.  Store this in Soln2.

Soln2 = A_transposeA\A_transposeY;

Define the x values to use for plotting the best-fit parabola.  This creates a vector x.

This is provided for you.

x=-4: 0.1 :4;

Define the best-fit parabola, storing it in yquadratic.  Elementwise multiplication of the x values times themselves to square them is achieved by using .* operator (because x is a vector).

yquadratic = Soln2(1) + Soln2(2)*x + Soln2(3)*(x.*x);

The following sequence of commands plots the data and the best-fit parabola.  The command is provided for you.

plot(x, yquadratic, X, Y, ‘k*’);grid;shg

Related; MAT350 8.2 MATLAB: Pseudoinverses.

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