[SNHU-ANSWER] MAT350 4.3 MATLAB: Span

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MAT350 4.3 MATLAB: Span

In this activity you will determine if a set of vectors spans a space and determine if a given vector is in the span of a set of vectors.

Consider the set of vectors in.

5          2          3            0

v1 = [ 4 ], v2 = [ 1], v3 = [ 1 ], v4 = [ 2 ]

2          -1         -3           6

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MAT350 4.3 MATLAB: Span

In this activity you will determine if a set of vectors spans a space and determine if a given vector is in the span of a set of vectors.

Consider the set of vectors in.

5          2          3            0

v1 = [ 4 ], v2 = [ 1], v3 = [ 1 ], v4 = [ 2 ]

2          -1         -3           6

 

A vector is an ordered n-tuple that can be represented as a row or column vector.  Here the vectors are rows.

v1 = [5 4 2]

v2 = [2 1 -1]

v3 = [3 1 -3]

v4 = [0 2 6]

 

To determine if this set of vectors spans 3-space, first create a matrix C consisting of the column vectors.

Note, the vectors were created as row vectors.  Use the dot-tic operator to make them column vectors.

Alternatively, you can create the vectors as column vectors to avoid using the dot-tic operator.

C = [v1.’ v2.’ v3.’ v4.’]

 

For vectors in 3-space, the reduced matrix will have three pivot columns if the vectors span 3-space.

reducedC = rref(C)

For this example, the reduced matrix has only two pivot columns, so the set of vectors does not span 3-space.

 

Consider the vector u=[2 1 1].  To determine if u is in the span of the given vectors,

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create an

augmented matrix [C|u].

u = [2 1 1]

Cu = [C u.’ ]

If a solution to the system Cx=u exists, then u is in the span of the vectors.

reducedCu = rref(Cu)

For this example, the reduced matrix has no solution to the system Cx=u, so u is not in the span of the vectors.

Utilize the following set of vectors in  for this activity.

 

1         2           1           0

v1 = [0 ], v2= [-2 ], v3= [ -1 ], v4= [ -1 ]

1         3           1           1

1         2           0           1

 

Enter vectors v1, v2, v3, and v4 as row vectors.

v1 = [1, 0, 1, 1]

v2 = [2, -2, 3, 2]

v3 = [1, -1, 1, 0]

v4 = [0, -1, 1, 1]

Create a matrix A consisting of these vectors as column vectors.

A = [v1′, v2′, v3′, v4′];

disp(A)

For vectors in 4-space, the reduced matrix will have four pivot columns if the vectors span 4-space.

Find the reduced matrix, storing it in reducedA.  Do the vectors span 4-space?

reducedA = rref(A);

disp(reducedA)

Create the vector w=[2 1 1 1].

w = [2, 1, 1, 1]

Create an augmented matrix [A|w], storing it in Aw.

Aw = [A, w’];

disp(Aw)

Find the reduced matrix, storing it in reducedAw.  Is w is in the span of the vectors?

reducedAw = rref(Aw);

disp(reducedAw)

Related; MAT350 4.13 MATLAB: Rank and Null Space.

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